Question

A body moves in circle cover half of revolution in 10 sec its linear distance became 10m along circumference of circle than its centripetal acceleration

Answer 1

The centripetal acceleration is $0.63 m/s^2$

Explanation:

The centripetal acceleration for an object in circular motion is given by

$a=\frac{v^2}{r}$

where

v is the linear speed

r is the radius of the circle

The body in the problem cover half of revolution in

t = 10 s

And the corresponding linear distance covered is

L = 10 m

which corresponds to half of the circumference, so

$L=2\pi r$

From this equation we find the radius of the circle:

$r=\frac{L}{2\pi}=\frac{10}{2\pi}=1.59 m$ [m]

While the linear speed is:

$v=\frac{L}{t}=\frac{10}{10}=1 m/s$

Therefore, the centripetal acceleration is

$a=\frac{1^2}{1.59}=0.63 m/s^2$

Learn more about circular motion:

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