Answer:
As shown below
Step-by-step explanation:
Given that when X denotes the errors in an experimental transmission channel, when checked by a certifier that detects missing pulses. follows the cumulative density function as given below:
[tex]F(x) = 0, 0<x<1\\ = 0.7, 1\leq X<4\\ =0.9, 4\leq X<7\\ = 1, x\geq 7[/tex]
[tex](a) P(X \leq 4) =F(4) = 0.9\\(b) P(X > 7)=1-F(8) = 0\\(c) P(X \leq 5)=F(6) = 0.9 \\(d) P(X> 4)=1-F(4)=1-0.9=0.1 \\(e) P(X \leq 2)=F(3) = 0.7[/tex]