Question

The mass of Mercury is 3.301 x 10^23 kg and its orbital radius is an average of 5.790 x 10^10 m. Calculate its linear momentum. (The orbital period of Mercury is 0.2409 years. Enter your answer in kg * m/s.)

Answer 1

To calculate the linear Moment of mercury it is necessary to consider the concepts related to the kinematic equations of movement description, for this particular case, the speed depending on the Orbital Period:

Our values are:

$R = 5.79*10^10 m$

$M_m = 3.301*10^{23} kg$

Period in seconds:

$T = 0.2409years$

$T = 0.2409year\frac{31556952}{1year}$

$T= 7602069.737s$

For definition velocity is,

$v = 2\pi\frac{R}{T}$ = $\frac{2\pi3.14(5.79*10^{10})}{7602069.737}$

$v = 47830.6977 m/s$

Linear momentum is defined as the product of a system's mass multiplied by its velocity:

$P = mv$

$P = (3.301*10^{23})(47830.6977)$

$P = 1.579*10^{28} kg m/s$