Question

Marlon school is selling tickets to the annual talent show. on the first day of ticket sales,the school sold 6 adult tickets and 4 tickets student tickets for a total of $96 the school took in $51 on the second day by selling 1 adult tickets and 3 student tickets. find the price of an adult ticket and the price of the student ticket​

Answer 1

Price of one adult ticket is $6 and one student ticket is $15.

Step-by-step explanation:

Let,

Adult tickets = x

Student tickets = y

According to statement, sales on day one;

6x+4y=96 Eqn 1

On second day;

x+3y=51 Eqn 2

$Multiplying\ Eqn\ 2\ by\ 6\\6(x+3y=51)\\6x+18y=306\ Eqn\ 3\\Subtracting\ Eqn\ 1\ from\ Eqn\ 3\\(6x+18y)-(6x+4y)=306-96\\6x+18y-6x-4y=210\\14y=210\\Dividing\ both\ sides\ by\ 14\\\frac{14y}{14}=\frac{210}{14}\\y=15$

Putting value of y in Eqn 2;

$x+3(15)=51\\x+45=51\\x=51-45\\x=6$

Price of one adult ticket is $6 and one student ticket is $15.

Keywords: Linear Equations, Multiplication.

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