Answer:
The Kinetic Energy of the guanabana is, K.E = 341.04 J
Explanation:
Given data,
The mass of the guanabana, m = 5.8 kg
The height of the fruit from the ground, h = 6 m
Let the potential energy at the ground be 0
According to the law of conservation of energy, the total energy of a system is conserved.
So, when the guanabana reaches the ground, the P.E is fully converted into K.E
The P.E at height h is
P.E = mgh
= 5.8 x 9.8 x 6
= 341.04 J
At ground 6 m drop,
P.E = K.E
Therefore, the Kinetic Energy of the guanabana is, K.E = 341.04 J
