Two air track carts move along an air track towards each other. Cart A has a mass of 450 g and moves toward the right with a speed of 0.850 m/s and air track cart B has a mass of 300 g and moves toward the left with a speed of 1.12 m/s. What is the total momentum of the system?
A) 0.719 kg•m/s toward the right
B) 0.719 kg•m/s toward the left
C) 0.750 kg•m/s toward the right
D) 0.047 kg•m/s toward the right
E) 0.750 kg•m/s toward the left

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mauricioalessandrell mauricioalessandrell · Answer 1 · 2019-11-21T07:58:03+01:00

Answer:

The right answer is D) the total momentum of the system is 0.047 kg · m/s toward the right.

Explanation:

Hi there!

The total momentum of the system is given by the sum of the momentum vectors of each cart. The momentum is calculated as follows:

p = m · v

Where:

p = momentum.

m = mass.

v = velocity.

Then, the momentum of the system will be the momentum of cart A plus the momentum of cart B (let´s consider the right as the positive direction):

mA · vA + mB · Vb

0.450 kg · 0.850 m/s + 0.300 kg · (- 1.12 m/s) = 0.047 kg · m/s

The right answer is D) the total momentum of the system is 0.047 kg · m/s toward the right.

okpalawalter8 okpalawalter8 · Answer 2 · 2022-04-01T12:08:37+02:00

The total momentum of the system is mathematically given as

M= 0.047 kg · m/s

Question Parameter(s):

Cart A has a mass of 450 g and moves toward the right with a speed of 0.850 m/s

air track cart B has a mass of 300 g

with a speed of 1.12 m/s.

Generally, the equation for the momentum is mathematically given as

M=mA · vA + mB · Vb

Therefore

M=0.450 kg · 0.850 m/s + 0.300 kg · (- 1.12 m/s)

M= 0.047 kg · m/s

In conclusion, the momentum

M= 0.047 kg · m/s