Question

ccording to a study by the Centers for Disease Control and Prevention, about 33% of U.S. births are Caesarean deliveries. Suppose seven expectant mothers are randomly selected. The expected number of mothers who will not have a Caesarean delivery is ______.

Answer 1

Answer:

Expected number of mothers who will not have a Caesarean delivery is seven.

Explanation:

P(C) = 0.33

P(C') = 1 - P(C) = 1 - 0.33 = 0.67

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Expected number of mothers who will not have a Caesarean delivery = n * P(C')

= 7 * 0.67

= 4.69