Answer:
a) [tex]V_H=0.056 (-i)m/s[/tex]
b) [tex]V_H=0.031 (-i)m/s[/tex]
Explanation:
By conservation of the linear momentum:
[tex]P_o = P_f[/tex]
[tex]0 = M_H*V_H+m_b*V_b[/tex]
[tex]V_H = m_b/M_H*V_b[/tex]
When the bullet is shot horizontally [tex]V_b = 965m/s[/tex]
[tex]V_H = -0.056m/s[/tex]
When the bullet is shot at 56.0° above the horizontal,
[tex]V_b = 965*[cos(56),sin(56)]m/s=[539.62;800.02]m/s[/tex]
Since on the y-axis ground will absorb the shock, we only make the calculations on the x-axis:
[tex]V_H = -0.031m/s[/tex]
[tex]V_H = -0.056m/s[/tex]