Answer:
2nd 4th and 5th theoretical probabilities are equal to 1/3.
Step-by-step explanation:
If a dice with six faces, having numbers (1-6) on each face is being rolled.
We will use the formula
[tex]P=\frac{\text{favorable outcome}}{\text{total number of possible outcomes}}[/tex]
(1) rolling an even number on the first roll.
Favorable outcome = 2,4,6 (3 numbers)
[tex]P=\frac{3}{6}=\frac{1}{2}[/tex]
(2) Landing on a star space on the first roll.
Maximum numbers of stars to be reached in first roll = 2
[tex]P=\frac{2}{6}=\frac{1}{3}[/tex]
(3) Landing at Cat Town on the first roll is not possible because it is at 9th place. and we can reach at 6 place on first roll only.
Therefore, [tex]P=\frac{0}{6}[/tex] =0
(4) Not landing on a question mark or star on the first roll.
Only 1 and 2 place has not question mark or star out of 6 places.
Favorable outcome will be = 2 (1 and 2)
[tex]P=\frac{2}{6}=\frac{1}{3}[/tex]
(5) Rolling a number greater than 4 on the first roll.
Favorable outcome = 2 ( 5 and 6)
[tex]P=\frac{2}{6}=\frac{1}{3}[/tex]
Therefore, 2nd 4th and 5th theoretical probabilities are equal to 1/3.