In order to solve this problem it is necessary to apply the conservation equations of the moment, specifically when it comes to problems of inelastic collision. The equation is given by,
[tex]m_1v_1+m_2v_2 = (m_1+m_2)v_f[/tex]
Since the problem is about an intersection, it is necessary to consider the velocity components for each one,
In the case of the car, if we define it on the vertical component we would have to,
[tex]m_1v_1 = (m_1+m_2)vsin\theta[/tex]
[tex]v_1 = \frac{(m_1+m_2)vsin\theta}{m_1}[/tex]
[tex]v_1 = \frac{(950+1900)(16)(sin(24))}{950}[/tex]
[tex]v_1 = 19.523m/s[/tex]
Therefore the velocity of the car before the collision is 19.523m/s
In the case of the truck we apply the velocity formula in the x component, then we would have,
[tex]m_2v_2 = (m_1+m_2)vcos\theta[/tex]
[tex]v_2 = \frac{(m_1+m_2)vcos\theta}{m_2}[/tex]
[tex]v_2 = \frac{(950+1900)(16)(cos(24))}{1900}[/tex]
[tex]v_2 = 21.925m/s[/tex]
Therefore the velocity of the truck before the collision is 21.9m/s