Question

A jogger runs with a velocity of 3.109 m/s NW over a period of 53.10 minutes. If the jogger initially ran SE for 911.9 m before changing direction and heading NW, what total distance did he run?

Answer 1

Answer:

The distance cover by Jogger before heading NW is 8993.3 meters

Explanation:

Given as :

Jogger initial distance in south east direction = 911.9 meters

The speed of Jogger in north west direction is 3.109 m/s

The time taken to cover distance in north west direction is 53.10 minutes

Or, the time taken = 53.10 × 60 sec

I.e Time taken = 3186 seconds

So, the Distance cover in north west direction = Speed × time

or, The Distance cover in north west direction = 3.109 mps × 3186 sec

Or,                                                                         = 9905.2 meters

So. before heading NW , the distance cover = 9905.2 m - 911.9 m = 8993.3 meters  

Hence The distance cover by Jogger before heading NW is 8993.3 meters Answer