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Answer:

Jenny save 4 times [tex]\$ 250[/tex] for the month

Step-by-step explanation:

Given Jenny has saved [tex]\$3,800[/tex] over the last 12 months.

She saved either [tex]\$250[/tex] or [tex]\$350[/tex] a month.

Let the number of months to save [tex]\$250[/tex] be x

Let the number of months to save [tex]\$350[/tex] be y

Total period is 12 month.

[tex]x+y=12 \ \ \ \ equation\ 1[/tex]

Jenny has saved $3,800 over the last 12 months.

[tex]250x+350y=3800[/tex]

Dividing both side from 50 we get,

[tex]\frac{250}{50}x+\frac{350}{50}y= \frac{3800}{50}[/tex]

[tex]5x+7y=76 \ \ \ \ equation\ 2[/tex]

Now Multiplying  equation 1 by 5 we get,

[tex]5\times(x+y)=5\times 12\\5x+5y=60\ \ \ \ equation \ 3[/tex]

Now Subtracting Equation 3 by equation 2 we get,

[tex](5x+7y=76)-(5x+5y=60)\\2y=16\\y=\frac{16}{2}= 8[/tex]

Substituting the value of y in equation 1 we get,

[tex]x+y=12\\x+8=12\\x=12-8\\x=4[/tex]

Jenny save 4 Months of  [tex]\$ 250[/tex] and 8 Months of  [tex]\$ 350[/tex]in a 12 month duration

Answer:

4 times

Step-by-step explanation:

Let,

250 = x

350 = y

x + y = 12

250x + 350y = 3,800

Solve the system.

x = 4 and y = 8

Therefore, Jenny saved $250 for 4 months and $350 for 8 months.

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