Respuesta :
Answer:
Jenny save 4 times [tex]\$ 250[/tex] for the month
Step-by-step explanation:
Given Jenny has saved [tex]\$3,800[/tex] over the last 12 months.
She saved either [tex]\$250[/tex] or [tex]\$350[/tex] a month.
Let the number of months to save [tex]\$250[/tex] be x
Let the number of months to save [tex]\$350[/tex] be y
Total period is 12 month.
[tex]x+y=12 \ \ \ \ equation\ 1[/tex]
Jenny has saved $3,800 over the last 12 months.
[tex]250x+350y=3800[/tex]
Dividing both side from 50 we get,
[tex]\frac{250}{50}x+\frac{350}{50}y= \frac{3800}{50}[/tex]
[tex]5x+7y=76 \ \ \ \ equation\ 2[/tex]
Now Multiplying equation 1 by 5 we get,
[tex]5\times(x+y)=5\times 12\\5x+5y=60\ \ \ \ equation \ 3[/tex]
Now Subtracting Equation 3 by equation 2 we get,
[tex](5x+7y=76)-(5x+5y=60)\\2y=16\\y=\frac{16}{2}= 8[/tex]
Substituting the value of y in equation 1 we get,
[tex]x+y=12\\x+8=12\\x=12-8\\x=4[/tex]
∴ Jenny save 4 Months of [tex]\$ 250[/tex] and 8 Months of [tex]\$ 350[/tex]in a 12 month duration
Answer:
4 times
Step-by-step explanation:
Let,
250 = x
350 = y
x + y = 12
250x + 350y = 3,800
Solve the system.
x = 4 and y = 8
Therefore, Jenny saved $250 for 4 months and $350 for 8 months.