Respuesta :
Answer:
2Al(NO₃)₃(aq) + 3Na₂SO₄(aq) → 1Al₂(SO₄)₃(s) + 6NaNO₃(aq)
2, 3, 1, 6
Second choice.
Step-by-step explanation:
Count the number of atoms on each side. Keep polyatomic ions together because they exist on both sides. After each coefficient you write in, recount the number of atoms.
Al(NO₃)₃(aq) + Na₂SO₄(aq) → Al₂(SO₄)₃(s) + NaNO₃(aq)
Al     1                  Al     2
NO₃   3                 NO₃    1
Na     2                 Na     1
SOâ‚„ Â Â Â 1 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â SOâ‚„ Â Â Â 3
Balance the sulfates (SOâ‚„) by multiplying it by 3 on the left. Sodium (Na) will also change.
Al(NO₃)₃(aq) + 3Na₂SO₄(aq) → Al₂(SO₄)₃(s) + NaNO₃(aq)
Al     1                  Al     2
NO₃   3                 NO₃    1
Na     6                 Na     1
SOâ‚„ Â Â Â 3 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â SOâ‚„ Â Â Â 3
Balance sodium (Na) by multiplying it on the left by 6. Nitrate (NO₃) will also change.
Al(NO₃)₃(aq) + 3Na₂SO₄(aq) → Al₂(SO₄)₃(s) + 6NaNO₃(aq)
Al     1                  Al     2
NO₃   3                 NO₃    6
Na     6                 Na     6
SOâ‚„ Â Â Â 3 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â SOâ‚„ Â Â Â 3
Balance the number of nitrates (NO₃) on the left. Multiply by 2. Aluminum (Al) also changes.
2Al(NO₃)₃(aq) + 3Na₂SO₄(aq) → Al₂(SO₄)₃(s) + 6NaNO₃(aq)
Al     2                  Al     2
NO₃   6                 NO₃    6
Na     6                 Na     6
SOâ‚„ Â Â Â 3 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â SOâ‚„ Â Â Â 3
The same number of each atom is on each side, so the equation is balanced.
If there is no coefficient, treat it as 1.
2,3,1,6