Answer:
4361.5 km/h
Explanation:
v = Velocity of space vehicle = 4300 km/h
[tex]v_1[/tex] = Velocity of exhaust
[tex]v_2[/tex] = Velocity of module
Relative velocity
[tex]v_r=v_2-v_1=82\\\Rightarrow v_1=v_2-82[/tex]
4m = Mass of rocket
m = Mass of module
3m = Mass of rocket without module
In this system linear momentum is conserved
[tex]4mv=3mv_1+mv_2\\\Rightarrow 4v=3(v_2-82)+v_2\\\Rightarrow 4\times 4300=3v_2-246+v_2\\\Rightarrow 17446=4v_2\\\Rightarrow v_2=\frac{17446}{4}\\\Rightarrow v_2=4361.5\ km/h[/tex]
The speed of the command module relative to Earth just after the separation is 4361.5 km/h