Fill in the blanks with the appropriate numbers for both electrons and bonds (considering that single bonds are counted as one, double bonds as two, and triple bonds as three). Drag the numbers on the left to the appropriate blanks on the right to complete the sentences. ResetHelp a. Fluorine has valence electrons and makes bond(s) in neutral compounds. b. Nitrogen has valence electrons and makes bond(s) in neutral compounds. c. Carbon has valence electrons and makes bond(s) in neutral compounds. d. Oxygen has valence electrons and makes bond(s) in neutral compounds.

(a) As, atomic number of fluorine is 9 and its electronic distribution is 2, 7. Hence, there are 7 valence electrons present in a fluorine atom. And, to attain stability it will readily gain one electron from a donor atom. Hence, it will make a single bond.

Therefore, fluorine has 7 valence electrons and makes 1 bond in neutral compounds.

(b) As, atomic number of nitrogen is 7 and its electronic distribution is 2, 5. Hence, there are 5 valence electrons present in a nitrogen atom. And, to attain stability it will gain three electrons from a donor atom. Hence, it will make a triple bond.

Therefore, nitrogen has 5 valence electrons and makes 3 bonds in neutral compounds.

(c) As, atomic number of carbon is 6 and its electronic distribution is 2, 4. Hence, there are 4 valence electrons present in a carbon atom. And, to attain stability it will readily share its valence electrons with another atom. Hence, it will make four bonds.

Therefore, carbon has 4 valence electrons and makes 4 bonds in neutral compounds.

(d) As, atomic number of oxygen is 8 and its electronic distribution is 2, 6. Hence, there are 6 valence electrons present in an oxygen atom. And, to attain stability it needs 2 electrons from another atom. Hence, it will make double bond.

Therefore, oxygen has 6 valence electrons and makes 2 bonds in neutral compounds.