Question

A simple ac circuit consists of an inductor connected across the terminals of an ac power source. If the frequency of the ac source is decreased by a factor of four, what happens to the reactance of the inductor

Answer 1

Answer:

reactance of the inductor increases by a factor of four.

Explanation:

Reactance of inductor X_L = Lω

$X_L= L(2\pi f)$

X_L∝f

$\frac{X_L_2}{X_L_1} =\frac{f_2}{f_1}$

Given $f_2 =\frac{f_1}{4}$

⇒f_2= f_1/4

$\frac{X_L_2}{X_L_1} = \frac{1}{4}$

therefore option we write it increases by a factor of four.