Answer:
minimum electric power consumption of the fan motor is 0.1437 Btu/s
Explanation:
given data
area = 3 ft by 3 ft
air density = 0.075 lbm/ft³
to find out
minimum electric power consumption of the fan motor
solution
we know that energy balance equation that is express as
E in - E out = [tex]\frac{dE \ system}{dt}[/tex] ......................1
and at steady state [tex]\frac{dE \ system}{dt}[/tex] = 0
so we can say from equation 1
E in = E out
so
minimum power required is
E in = W = m [tex]\frac{V^2}{2}[/tex] = [tex]\rho A V \frac{V^2}{2}[/tex]
put here value
E in = [tex]\rho A V \frac{V^2}{2}[/tex]
E in = [tex]0.075 *3*3* 22 \frac{22^2}{2}[/tex]
E in = 0.1437 Btu/s
minimum electric power consumption of the fan motor is 0.1437 Btu/s