Answer:0.21
Explanation:
Given
mass of turtle [tex]m=12 kg[/tex]
velocity of Truck [tex]v=55 mi/h\approx 24.58 m/s[/tex]
time taken to stop [tex]t=12 s[/tex]
using [tex]v=u+at[/tex]
where v=final velocity
u=initial velocity
a=acceleration
t=time
[tex]0=24.58+a\cdot 12[/tex]
[tex]a=-\frac{24.58}{12}[/tex]
[tex]a=-2.04 m/s^2[/tex]
therefore 2.04 is the deceleration experienced by turtle which is countered by frictional force
[tex]a=\mu g[/tex] ,where [tex]\mu =[/tex]coefficient of friction
[tex]2.04=\mu \times 9.8[/tex]
[tex]\mu =0.209\approx 0.21[/tex]