Question

If a polynomial function f(x) has roots 0, 4, and 3+the root of
11, what must also be a root of fx)?

Answer 1

Answer:

3 - $\sqrt{11}$

Step-by-step explanation:

Note that radical roots occur in conjugate pairs, thus

3 + $\sqrt{11}$ is a root then 3 - $\sqrt{11}$ is also a root