Answe
given,
combined mass of two people = 140 Kg
compression of spring = 8.70 cm
time period = 1.66 s
we know,
F = k x
where k is spring constant
and also
F = mg
equating both the force equation
k x = mg
[tex]k = \dfrac{mg}{x}[/tex]
[tex]k = \dfrac{140 \times 9.8}{0.087}[/tex]
k = 15770 N/m
total mass = 140 + m_c
period of oscillation
[tex]T = 2 \pi \sqrt{\dfrac{total\ mass}{k}}[/tex]
[tex]1.66 = 2 \pi \sqrt{\dfrac{140 + m_c}{15770}}[/tex]
140 + m_c = 1100
m_c = 960 Kg
a) total load supported by the car
P = 1100 Kg
b) mass of car = 960 Kg