Question

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
The degree of the function Fx) = -(x + 1)2(2x - 3)(x+ 2)? Is
1
, and its y-intercept is ( 0
,0
).

Answer 1

Answer:

Degree:3

Y-intercept:-6

Step-by-step explanation:

The given function is:

$f(x) = - {(x + 1)}^{2}( {2x - 3)}(x +2 )$

To find the degree, we multiply out the leading terms of each factor.

The leading term of the first factor is:

$- {x}^{2}$

and that of the second factor is

$2x$

and the third one is:

$x$

If we multiply out the leading terms, we would get:

$- {x}^{2} \times 2x \times x = - 2 {x}^{3}$

Therefore the degree of the function is:

3

To find the y-intercept, we put x=0 to get:

$f(0) = - {(0 + 1)}^{2}( {2 \times 0 - 3)}(0 +2 )$

$\implies \: f(0) = ( 1)( - 3) \times (2) = - 6$