Question

Rewrite the expression g+1/6d-3/4g+1/9g-g+1/4d in STANDARD FORM I NEED THIS ASAP AND I NEED ALL STEPS!

Answer 1

Answer:

$-\frac{23}{36}g+\frac{5}{12}d$

Step-by-step explanation:

Given:

$g+\frac{1}{6}d-\frac{3}{4}g+\frac{1}{9}g-g+\frac{1}{4}d$

Solving for g and d we get,

$g+\frac{1}{6}d-\frac{3}{4}g+\frac{1}{9}g-g+\frac{1}{4}d\\\frac{1}{6}d-\frac{3}{4}g+\frac{1}{9}g+\frac{1}{4}d$

Now taking LCM for all we get,

$\frac{1\times6}{6\times6}d-\frac{3\times9}{4\times9}g+\frac{1\times 4}{9\times4}g+\frac{1\times 9}{4\times 9}d\\\frac{6}{36}d-\frac{27}{36}g+\frac{4}{36}g+\frac{9}{36}d\\\frac{6d-27g+4g+9d}{36}\\\frac{-23g+15d}{36}\\-\frac{23}{36}g+\frac{15}{36}d\\-\frac{23}{36}g+\frac{5}{9}d$