Question

PLEASE PLEASE ANSWER THIS QUESTION IN THE NEXT 2MINUTES RIGHT NOW!!!!!! On a coordinate plane, a line goes through (1, negative 1) and (4, 2). A point is at (2, 5). What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (2, 5)? y + 5 = x + 2 y − 2 = x − 5 y − 5 = −(x − 2) y + 2 = −(x +

Answer 1

Answer:

$y - 5 = - 1(x - 2)$

Step-by-step explanation:

First, we find the equation of the line that goes through;

(1,-1) and (4,2).

Using the formula:

$m = \frac{y_2-y_1}{x_2-x_1}$

We substitute to get:

$m = \frac{2 - - 1}{4 - 1}$

$m = \frac{3}{3} = 1$

The slope of the line that is perpendicular to this line is -1.

If this line passes through:

(2,5)

When its equation is given by:

$y=m(x-x_1)+y_1$

$y= - 1(x-2)+5$

Or the point slope form is

$y - 5 = - 1(x - 2)$

Answer 2

Answer:

C. y − 5 = −(x − 2) on Ed g e n u i t y

Step-by-step explanation: