Insert the values from the question above for x, y, z, & n into KxFey(C204)z nH20 anod provide the correct coefficients to balance the following equation Fe(NH4 )2(SO4 )2.6H20+_H2C204+_K2C204+-H202 → K,Fey C204)z nH20+(NH4)2SO4+ H2S04+H20 (Hint: Remember H202, an oxidizing agent, was used in the synthesis, so you'll need to do a redox balance. Start with just the iron ions, balance the reaction, and then add the full formulas.)
