Answer:
B) [tex]\frac{2}{6}\times \frac{1}{5}[/tex]
Step-by-step explanation:
Number of blue marbles =[tex]N(blue)=4[/tex]
Number of green marbles=[tex]N(green)=2[/tex]
Total number of balls=[tex]N=N(blue)+N(green)=4+2=6[/tex]
Probability of drawing a green marble on first draw= [tex]P(green_1)=\frac{N(green)}{N}=\frac{2}{6}[/tex]
After drawing a green marble a 2nd draw is made without replacement.
So, now [tex]N(green)=2-1=1[/tex] and [tex]N=6-1=5[/tex]
Probability of drawing a green marble on 2nd draw=[tex]\frac{N(green)}{N}=P(green_2)=\frac{1}{5}[/tex]
∴ Probability of drawing a green marble on both your first and second draws=[tex]P(green_1)\times P(green_2)=\frac{2}{6}\times \frac{1}{5}[/tex]
