Question

A rod 30 cm long moves in a plane perpendicular to a magnetic field of 505 G. The velocity of the rod is perpendicular to its length. Find the speed of the rod if the potential difference between the ends is 6 V.

Answer 1

Answer:

Speed, v = 396.03 m/s

Explanation:

It is given that,

Length of the rod, l = 30 cm = 0.3 m

Magnetic field, $B = 505\ G=0.0505\ T$

The potential difference between the ends is 6 V, E = 6 V

The rod moves in a plane perpendicular to a magnetic field with some speed. Due to this motion an emf is induced it it. It is given by :

$\epsilon=Blv$

Where

v is the speed of rod

$v=\dfrac{\epsilon}{Bl}$

$v=\dfrac{6}{0.0505\times 0.3}$

v = 396.03 m/s

So, the speed of the rod is 396.03 m/s. Hence, this is the required solution.

Answer 2

Answer:

Speed of the rod $v=396.03m/s$

Explanation:

Given

Length of the rod  $\mathrm{l}=30 \mathrm{~cm}=0.3 \mathrm{~m}$

Magnetic field, $B=505 G=0.0505 T$

• The potential difference between the ends is $\mathrm{E}=6 \mathrm{~V}$
• The rod moves in a plane perpendicular to a magnetic field with some speed.

Due to this motion an emf is induced it. It is given by:

$\epsilon=B l v$

Where

$v$ is the speed of rod $v=\frac{\epsilon}{B l}$

$v=\frac{6}{0.0505 \times 0.3}$

$\mathrm{v}=396.03 \mathrm{~m} / \mathrm{s}$

To learn more, refer:

https://brainly.com/question/15518924