Question

A volleyball is spiked so that its incoming velocity of +4.37 m/s is changed to an outgoing velocity of -10.5 m/s. The mass of the volleyball is 0.350 kg. What is the magnitude of the impulse that the player applies to the ball?

Answer 1

Answer:

-5.20 kg.m/s

Explanation:

Impulse is another word for change in momentum. It is calculated according to the following formula

impulse  = final momentum - initial momentum

$impulse = mv_{f} - mv_{i} \\              = -10.5*0.350 - 0.350*4.37\\              = -5.20 kg.m/s$

It is important to pay close attention to the signs to ensure that no mistakes are made. Impulse is a vector so the direction of velocity is important in the calculation because very often it determines the direction of the impulse