Question

Write the balanced chemical equation for each of these reactions. Include phases.

1) When aqueous sodium hydroxide is added to a solution containing lead(II) nitrate, a solid precipitate forms.

2) However, when additional aqueous hydroxide is added the precipitate redissolves forming a soluble Pb(OH)42-(aq) complex ion

Answer 1

Answer: The chemical equations are given below.

Explanation:

• For 1:

The chemical equation for the reaction of lead nitrate and sodium hydroxide follows:

$Pb(NO_3)_2(aq.)+2NaOH(aq.)\rightarrow Pb(OH)_2(s)+2NaNO_3(aq.)$

By Stoichiometry of the reaction:

1 mole of aqueous solution of lead nitrate reacts with 2 moles of aqueous solution of sodium hydroxide to produce 1 mole of solid lead hydroxide and 2 moles of aqueous solution of sodium nitrate.

• For 2:

The chemical equation for the reaction of lead hydroxide and hydroxide ions follows:

$Pb(OH)_2(s)+2OH^-(aq.)\rightarrow [Pb(OH)_4]^{2-}(aq.)$

By Stoichiometry of the reaction:

1 mole of lead hydroxide reacts with 2 moles of aqueous solution of hydroxide ions to produce 1 mole of aqueous solution of tetra hydroxy lead (II) complex

Hence, the chemical equations are given above.

Answer 2

The balanced chemical equation for each of the reactions is as follows:

• Pb(NO3)2(aq) + 2NaOH(aq) → 2 NaNO3(aq) + Pb(OH)2(s)
• Pb(OH)2 + 2OH- → Pb(OH)42-

How to balance chemical equation?

A chemical equation is said to be balanced when the number of atoms of each element on both sides of the equation are the same.

According to this question, when aqueous sodium hydroxide is added to a solution containing lead(II) nitrate, a solid precipitate forms. The balanced equation are as follows:

Pb(NO3)2(aq) + 2NaOH(aq) → 2 NaNO3(aq) + Pb(OH)2(s)

Also, when additional aqueous hydroxide is added the precipitate redissolves forming a soluble Pb(OH)42-(aq) complex ion. The balanced equation is as follows:

Pb(OH)2 + 2OH- → Pb(OH)42-

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