204 moles of water and 192 moles of carbon dioxide.
2C₁₆H₃₄ + 49O₂ → 32CO₂ + 34H₂O
We are given 12 moles of diesel
Required to determine the number of moles of water and carbon dioxide.
2 moles of diesel reacts to generate 32 moles of carbon dioxide and 34 moles of water.
Therefore;
Moles of water = moles of diesel × 34/2
= 12 moles × 34/2
= 204 moles
Moles of Carbon dioxide = Moles of diesel × 32/2
= 12 moles × 32/2
= 192 moles
Therefore, the combustion of 12 moles of diesel yields 204 moles of water and 192 moles of carbon dioxide.