Question

In a certain type of wild flower, red is the dominant color and white is the recessive color. Phenotypic red flowers can be either homozygous dominant (WW) or heterozygous (Ww) in genotype. Whereas, the phenotypic white flowers are always homozygous recessive (ww). The phenotypic characteristics of a field of flowers were studied by a group of researches, 649% of the flowers were phenotypically red What percent of the flowers are genotypically heterozygous (ww? A. 36% B. 48% ° C. 64% O D. 24%

Answer 1

Answer:

Option B

Explanation:

It is given that red is dominant color and white is  recessive color

Let the red color be represented by "W" , then the white color will be represented by "w"

It is given that $64$% of the flowers are red in color phenotypically.

Now let us assume that the given population is in Hardy Weinberg's equilibrium.

Then, as per the second rule of Hardy Weinberg,

$p^2+2pq+q^2=1$

Here $p^2$ and $2pq$ represent homozygous and heterozygous red flowers

Therefore, white recessive flowers genotype frequency would be

$q^ 2 = 1- (p^2+2pq)\\q^2 = 1- 0.64\\q^2 = 0.36$

Frequency of recessive allele is equal to

$q^2 = 0.36\\q= \sqrt{0.36} \\q = 0.6$

Frequency of dominant allele is equal to

$p = 1-q\\p = 1- 0.6\\p= 0.4$

Now  Frequency of dominant genotype "WW"  is equal to $p^2 = 0.4^2 = 0.16$

Frequency of heterozygous red genotype "Ww"

$0.64 - 0.16 \\= 0.48$