Question

Kayden is a stunt driver. One time, during a gig where she escaped from a building about to explode(!), she drove at a constant speed to get to the safe zone that was 160 meters away. After 3 seconds of driving, she was 85 meters away from the safe zone. Let D represent the distance (in meters) from the safe zone after t seconds. Complete the equation for the relationship between the distance and number of seconds.

Answer 1

$d=160-25t$

Step-by-step explanation:

Let $d$ be the distance between Kayden and safe zone at any time.

It is given that initially $d=160$

Lrt her speed be $v$

Since the speed is constant,the distance covered by her in $t$ seconds=$v\times t$

So,the distance between her and safe zone after $t$ seconds is $160-vt$

It is given that after $3$ seconds,$d=85$

So,$160-3v=85$

$3v=75$

$v=25$

So,$d=160-3t$

Answer 2

Answer:

y=-25x+160

Step-by-step explanation: