Respuesta :
Answer:
Point cannot be inside ∠AOB
Step-by-step explanation:
Consider the provided information.
m∠COB = 50°30’, m∠AOB = 70° and m∠AOC = 20°30’.
The angle addition postulate states that if C is in the interior of AOB , then
m∠AOC+m∠COB=m∠AOB
Substitute the respective values in above.
[tex]20\°30'+50\°30'=70\°[/tex]
[tex]30'+30'=60'=1\°[/tex] (∵ 1 degree is equal to 60 minutes )
[tex]71\°=70\°[/tex]
Which is false.
Hence, point cannot be inside ∠AOB
Answer:
No, Point cannot be inside ∠AOB.
Step-by-step explanation:
Given information: m∠COB = 50°30’, m∠AOB = 70° and m∠AOC = 20°30’.
1 degree = 60 minutes
Using this conversion we get
m∠COB = 50°30’ = 50.5°
m∠AOB = 70°
m∠AOC = 20°30’ =20.5°
Let as assume C is in the interior of ∠AOB , then
m∠AOC+m∠COB=m∠AOB (angle addition postulate)
Taking LHS,
LHS = m∠AOC + m∠COB = 20.5° + 50.5° = 71°
Taking RHS,
RHS = m∠AOB = 70°
LHS ≠ RHS
It means our assumption is wrong.
Therefore, point C cannot be in the interior of ∠AOB.
