In recent years, astronomers have found planets orbiting nearby stars that are quite different from planets in our solar system. Kepler-12b, has a diameter that is 1.7 times that of Jupiter, but a mass that is only 0.43 that of Jupiter. What is the value of g on this large, but low-density, world?

Respuesta :

Answer:

The value of g in Kepler-12b is [tex]3.85 m/s^{2}[/tex]

Explanation:

To determine the value of g at Kepler-12b it is necessary to combine the equation of the weight and the equation for the Universal law of gravity:

[tex]W = m.g[/tex]  (1)

Where m is the mass and g is the value of the gravity

[tex]F = G \frac{M.m}{R^{2}}[/tex]  (2)

Equation (1) and equation (2) will be equal, since the weight is a force acting on the object as a consequence of gravity:

[tex]m.g = G \frac{M.m}{R^{2}}[/tex]  (3)

Then g will be isolated from equation 3:

[tex]g = G \frac{M.m}{m.R^{2}}[/tex]

[tex]g = \frac{G.M}{R^{2}}[/tex]  (4)

The radius of Jupiter has a value of 69911000 meters, so its diameter can be determined by:

[tex]d = 2R[/tex] (5)

Where d and R are the diameter and radius of Jupiter

[tex]d_{jupiter} = 2(69911000 m)[/tex]

[tex]d_{jupiter} = 139822000 m[/tex]

Procedure for finding the radius of Kepler-12b:

For the case of Kepler-12b it has a diameter that is 1.7 times that of Jupiter

[tex]d_{Kepler-12b} = 1.7(d_{jupiter})[/tex]

[tex]d_{Kepler-12b} = 1.7(139822000 m)[/tex]

[tex]d_{Kepler-12b} = 237697400 m[/tex]

By means of equation 5 the radius of Kepler-12b can be known:

[tex]R_{Kepler-12b} = \frac{d}{2}[/tex]

[tex]R_{Kepler-12b} = \frac{237697400 m}{2}[/tex]

[tex]R_{Kepler-12b} = 118848700 m[/tex]

Procedure for finding the mass of Kepler-12b:

The mass of Jupiter has a value of [tex]1.898x10^{27}[/tex] kilograms

For the case of Kepler-12b it has a mass that is 0.43 times that of jupiter

[tex]m_{Kepler-12b} = 0.43(m_{jupiter})[/tex]

[tex]m_{Kepler-12b} = 0.43(1.898x10^{27} Kg)[/tex]

[tex]m_{Kepler-12b} = 8.161x10^{26} Kg[/tex]

The value of g in Kepler-12b can be found by replacing its radius and mass in equation 4:

[tex]g = \frac{(6.67x10^{-11} N.m^{2}/Kg^{2})(8.161x10^{26} Kg)}{(118848700 m)^{2}}[/tex]

[tex]g = 3.85 m/s^{2}[/tex]

Hence, in Kepler-12b the gravity has a value of [tex]3.85 m/s^{2}[/tex]

ACCESS MORE