Answer:
6,226 tiles of 9 in are needed to cover an area of 400 square feet
Step-by-step explanation:
Let
A -----> an area in square feet
t(A) ---> the total number of 9 in. tiles needed
we have
[tex]t(A)=\frac{144A}{9.252}[/tex]
For A=400 ft^2
substitute in the equation and solve for t
[tex]t(400)=\frac{144(400)}{9.252}\\\\t(400)=6,226\ tiles[/tex]
That means -----> 6,226 tiles of 9 in are needed to cover an area of 400 square feet