Question

A 0.580-kg rock is tied to the end of a string and is swung in a circle with a radius of 0.500 meters. The
velocity of the rock is 4.50 m/s. What is the centripetal force acting on the rock?
5.22 N
23.5 N
69.8 N
15.5 N

Answer 1

Answer:

23.5 N

Explanation:

We are given;

• Mass of the rock, m as 0.580 kg
• Radius of the circle, r as 0.50 meters
• Velocity of the rock is 4.50 m/s

We are required to calculate the centrifugal force.

First, we need to know what is centripetal force.

• Centripetal force is the force that maintains the object in a circular motion. The force acts towards the center of a circular path.

Second we need to know how it is calculated.

• Centripetal force is calculated using the formula,

$Fc=\frac{Mv^{2} }{r}$

Third, we answer our question.

$Centripetal force=\frac{(0.580kg)(4.5^{2})}{0.50m}$

                              $=23.49Newtons$

                              $=23.5Newtons$

Thus, the centripetal force acting on the rock is 23.5 Newtons

Answer 2

Answer:

23.5 Newtons

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