Question

Find the slant height for a right circular cone with a radius of 3 and a height of 5.

4
√(31)
√(34

Answer 1

Answer: l = $\sqrt{34}$

Step-by-step explanation:

The slant height of a cone is given by

l = $\sqrt{h^{2}+r^{2}  }$

h= 5

r = 3

Therefore :

l = $\sqrt{5^{2}+3^{2}  }$

l= $\sqrt{25+9}$

l = $\sqrt{34}$

Answer 2

Answer:

The slant height is √34

Step-by-step explanation:

This problem bothers on mensuration of shapes, in particular the cone

We can solve for the slant height of a cone using Pythagoras theorem

N/B kindly see attached for your reference

Assuming all units in cm

Given data

Say that the slant height is x

Radius r= 3cm

Height h= 5cm

Applying Pythagoras theorem we have

x²=h²+r²

x=√h²+r²

Substituting our data into the expression we have

x=√5²+3²

x=√25+9

x=√34

The slant height is x=√34