Answer:
The required division problem he must solve is:
[tex]\frac{2}{3} \div \frac{-3}{8} =\frac{2}{3}\times\frac{-8}{3}=\frac{-16}{9}[/tex]
Step-by-step explanation:
Consider the provided information.
Martin chose two of the cards below. When he found the quotient of the numbers, his answer was -16/9.
As we know that the quotient of the number is a negative number.
Therefore, the sign of both numbers must be different,
Thus we can concluded he must select [tex]\frac{2}{3}[/tex] as one of the card, so that product is a negative number.
Let the selected card be x.
[tex]\frac{2}{3} \div x =\frac{-16}{9}\\\\x=\frac{2}{3}\div\frac{-16}{9}\\\\x=\frac{2}{3}\times\frac{-9}{16}\\\\x=\frac{-3}{8}[/tex]
Hence, the two cards should be [tex]\frac{2}{3}[/tex] and [tex]\frac{-3}{8}[/tex]
The required division problem he must solve is:
[tex]\frac{2}{3} \div \frac{-3}{8} =\frac{2}{3}\times\frac{-8}{3}=\frac{-16}{9}[/tex]
