Answer:
143.37 K or °C
Explanation:
We are given;
- Mass of silver block = 250 g
- Quantity of heat, Q = 2000 calories
We are required to determine change in temperature for the block of ice.
- We know that heat absorbed or released is calculated by;
Q = m × c × ΔT, where M is the mass of an object, c is the specific heat capacity and ΔT is the change in temperature.
In this case;
Q = 2000 calories
Mass = 250 g
specific heat , c of silver is 0.0558 cal/g°C
Therefore;
Rearranging the formula;
ΔT = Q ÷ mc
= 2000 cal ÷ (250 g × 0.0558 cal/g°C)
= 143.37 °C or K
The change in temperature is 143.37 K or °C
