Answer:104.853 kPa
Explanation:
Given
Depth of water [tex]h_2=22 cm[/tex]
on the top of water a layer of [tex]h_1=28 cm[/tex] oil layer is present
specific gravity of oil [tex]\rho _o=0.5\rho _w[/tex]
Assuming Atmospheric Pressure to be [tex]101.325 KPa[/tex]
We know Pressure due to Pressure Difference is given by
[tex]\Delta P=\rho \times g\times h[/tex]
[tex]\Delta P=\rho _0\times g\times h_1+\rho _w\times g\times h_2[/tex]
[tex]\Delta P=0.5\rho _w\times g\times h_1+\rho _w\times g\times h_2[/tex]
[tex]\Delta P=0.5\times 1000 \times 9.8\times 0.28+1000\times 9.8\times 0.22[/tex]
[tex]\Delta P=1.372\times 10^3+2.156\times 10^3[/tex]
[tex]\Delta P=3.528 kPa[/tex]
[tex]Absolute\ Pressure=Atmospheric\ Pressure+\Delta P=101.325+3.528[/tex]
[tex]Absolute\ Pressure =101.325+3.528=104.853 kPa[/tex]