Answer:$ 260
Step-by-step explanation:
Given
Initially 460 passenger travels
It cost $ 4000 +$60 per passenger
If ticket Price is $ T
then they expect 460-T passengers
Total Revenue generated by tickets[tex]=T\times (460-T)[/tex]
cost to airlines [tex]=4000+60\times (460-T)[/tex]
Profit is [tex]=T\times (460-T)-4000-60\times (460-T)[/tex]
[tex]P=(460-T)(T-60)-4000[/tex]
To get maximum Profit differentiate P w.r.t to T and Equate it to zero
[tex]\frac{\mathrm{d} P}{\mathrm{d} T}=\frac{\mathrm{d} }{\mathrm{d} (460-T)(T-60)T}-0[/tex]
[tex]\frac{\mathrm{d} P}{\mathrm{d} T}=-T+60+460-T=0[/tex]
[tex]520=2T[/tex]
[tex]T=260[/tex]
Therefore it cost $ 260 to get maximum Profit