Question

Calcium carbonate decomposes at 1200.0°C and forms carbon dioxide and calcium oxide. If 33.0 L of carbon
dioxide is collected at 1200.0° C and is then cooled to 30 °C, what is the new volume of carbon dioxide gas?

Answer 1

Answer:

$\large\boxed{\text{6.79 L}}$

Explanation:

The pressure is constant, so, to calculate the volume, we can use Charles' Law.

$\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}$

Data:

V₁ = 3300 L; T₁ = 1200.0 °C

V₂ = ?;          T₂ =     30    °C

Calculations:

(a) Convert temperatures to kelvins

T₁ = (1200.0 + 273.15) K = 1473.15 K

T₂ =    (30    + 273.15) K =  303.15 K

(b) Calculate the new volume

$\dfrac{33.0}{1473.15} = \dfrac{V_{2}}{303.15}\\\\{ V_{2}} = \dfrac{33.0\times 303.15}{1473.15} = \textbf{6.79 L}\\\\\text{The new volume of the gas is \large \boxed{\textbf{6.79 L}} }$