Question

A particle whose mass m=2 kg moves in the xy plane with a constant speed v= 3 m/s in the x direction along the line y = 5. What is its angular momentum (magnitude and direction) relative to the origin?

Answer 1

Answer:

L= 30  kg.m²/s

Explanation:

Given that

m = 2 kg

v= 3 m/s along x direction

y= 5 m

As we know that

Linear momentum P

P = m v

The angular momentum is the moment of linear momentum.

So the angular momentum L

L = m v r

Here r= 5 m

By putting the values

L = m v r

L = 2 x 3 x 5  kg.m²/s

L= 30  kg.m²/s