Answer:b)1770 kWh
Explanation:
Given
volume of water [tex]V=40,000 gallons[/tex]
Temperature rise [tex]\Delta T=10^{\circ}C[/tex]
[tex]c=4186 J/kg-^{\circ} C [/tex]
also 1 kg mass is approximately is 1 gallon
therefore 40,000 gallon is equivalent to 3.8\times 40000 kg
heat Required to raise temperature is
[tex]Q=mc\Delta T[/tex]
[tex]Q=3.8\times 40000\times 4186\times 10 [/tex]
[tex]Q=63,627.2\times 10^5 J[/tex]
[tex]Q=63,672.2\times 10^2 KJ[/tex]
[tex]Q=1767.42 kWh\approx 1770 kWh[/tex]