Answer:
ρ = 1.8 10⁹ kg / m³
Explanation:
The very useful concept of density is defined as the relationship between more than one body and its volume
ρ = m / V
In this case we assume that the white dwarf in a sphere, so its volume is
V = 4/3 π R³
Let's reduce the magnitudes to the SI system
Mass of the star M = 1.0 Msun (1,991 1030kg / 1mSun) = 1,991 10³⁰kg
Star radii R = 6400 km (1000m / 1km) = 6.4 10⁶ m
Let's calculate
V = 4/3 π (6.4 10⁶)³
V = 1,098 10²¹ m³
ρ = 1,991 10³⁰ / 1,098 10²¹
ρ = 1.8 10⁹ kg / m³
We compare with some materials
Water 997 kg / m³
Steel 7850 kg / m³
aluminum 2700 kg / m³
We see that the density of the star is much order of magnitude greater than that of ordinary materials
