Respuesta :

Step-by-step explanation:

Consider the provided function.

[tex]f(x)=4(\frac{1}{3})^{2x}[/tex]

Apply exponent rule: [tex]\left(\frac{a}{b}\right)^c=\frac{a^c}{b^c}[/tex]

[tex]f(x)=4(\frac{1^2}{3^2})^x[/tex]

[tex]f(x)=4(\frac{1}{9})^x[/tex]

Hence, the required function is [tex]f(x)=4(\frac{1}{9})^x[/tex]

OR

If the function is [tex]f(x)=4(\frac{1}{3})^2x[/tex]

Apply exponent rule: [tex]\left(\frac{a}{b}\right)^c=\frac{a^c}{b^c}[/tex]

[tex]f(x)=4(\frac{1^2}{3^2})x[/tex]

[tex]f(x)=4(\frac{1}{9})x[/tex]

[tex]f(x)=\frac{4x}{9}[/tex]

Hence, the required function is [tex]f(x)=\frac{4x}{9}[/tex]

Answer:

f(x)=4([tex]\frac{1}{9}[/tex])^x

Step-by-step explanation:

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