Question

Write the expression 2a+b in the form of a fraction with a denominator of
1) 2a-b

2) 3a

PLEASE HELP ASAP

Answer 1

Answer:

Part 1  =  $\frac{4a^{2} -b^{2} }{2a-b}$

Part 2 =  $\frac{6a^{2} +3ab }{3a}$

Step-by-step explanation:

Let the fraction be denoted by numerator and denominator then given denominator for the first expression contains 2a-b.

let us assume that the numerator contains x

now given that 2a+b is the value of the expression  which means

$2a+b=\frac{x}{2a-b}$

$x=4a^{2} -b^{2}$

Therefore the fraction for the first option is $\frac{4a^{2} -b^{2} }{2a-b}$

Given the denominator for the second expression is 3a.

Let us assume that  the numerator contains x

Now given that 2a+b is the value of the expression which means

$2a+b=\frac{x}{3a}$

$x=6a^{2} +3ab$

Therefore the fraction for the second option is $\frac{6a^{2} +3ab }{3a}$