heres another math problem
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Answer:
[tex]\therefore x=50\°[/tex]
Step-by-step explanation:
Let the angle between [tex]2x[/tex] and 150° be = b°
[tex]150\°+b\°=180\°[/tex] [ Forming a linear pair of angles]
Solving for [tex]b[/tex] by subtracting both sides by 150.
[tex]150+b-150=180-150[/tex]
∴ [tex]b=30\°[/tex]
[tex]50\°+2x+b\°=180\°\\[/tex] [Angle lying on a straight line add up to 180]
Plugging in [tex]b=30\°[/tex]
[tex]50+2x+30=180\\2x+80=180[/tex]
Solving for [tex]x[/tex] by
subtracting both sides by 80.
[tex]2x+80-80=180-80\\2x=100[/tex]
then dividing both sides by 2.
[tex]\frac{2x}{2}=\frac{100}{2}\\\\\therefore x=50\°[/tex]
Answer:
50°
Step-by-step explanation:
Now look at the straight line below,We know that in a straight line sum of all angles is equal to 180°. so the remaining unknown angle in that line is 180°-150°=30° and that angle is equal to the angle in the upper straight line as they are vertically opposite angles in the intersection of two straight lines.
Now apply the same concept for the upper straight line also that is sum of the angles 30° and 50° and 2x° is equal to 180° .
30+50+2x=180.
->80+2x=180.
->2x=100
x=50°