Answer:
see the explanation
Step-by-step explanation:
we know that
In an Arithmetic Sequence the difference between one term and the next is a constant called the common difference
we have
[tex]3, 8, 13, 18, 23,...[/tex]
Let
[tex]a_1=3\\a_2=8\\a_3=13\\a_4=18\\a_5=23\\[/tex]
[tex]a_2-a_1=8-3=5[/tex] ------>[tex]a_2=a_1+5[/tex]
[tex]a_3-a_2=13-8=5[/tex] ------>[tex]a_3=a_2+5[/tex]
[tex]a_4-a_3=18-13=5[/tex] ------>[tex]a_4=a_3+5[/tex]
[tex]a_5-a_4=23-18=5[/tex] ------>[tex]a_5=a_4+5[/tex]
so
the common difference between consecutive terms is equal to 5
we can rewrite the formula as
[tex]a_n=a_(_n_-_1_)+5[/tex] -----> given formula
For n > 1
where
an is the term that you want to find (position n)
a(n-1) is the known term position (n-1)
Find a_8
For n=8
[tex]a_8=a_(_8_-_1_)+5[/tex]
[tex]a_8=a_7+5[/tex]
I need to know a_7
or
we know that
The general formula for arithmetic sequence is equal to
[tex]a_n=a_1+d(n-1)[/tex]
where
an is the term that you want to find (position n)
a_1 is the first term
d is the common difference
n is the number of terms
we have
[tex]a_1=3[/tex]
[tex]d=5[/tex]
substitute
[tex]a_n=3+5(n-1)[/tex]
[tex]a_n=3+5n-5[/tex]
[tex]a_n=5n-2[/tex]
so
For n=8
[tex]a_8=5(8)-2[/tex]
[tex]a_8=38[/tex]