Question

how do you find the derivative of h(t)=sqrt(t)(1-t^2)

Answer 1

Answer:

Step-by-step explanation:

$h(t)=\sqrt{(t)(1-t^2)}\\h^{2}(t)=t(1-t^2)=t-t^3\\ diff. w.r.t.,\\2 h(t)h'(t)=1-3t^2\\h'(t)=\frac{1-3t^2}{2 h(t)} \\h'(t)=\frac{1-3t^2}{2\sqrt{(t)(1-t^2)} }$