Question

A restaurant serves sandwiches and salads. They sold 14 sandwiches and 14 salads for a total of $280 for lunch. In the evening, 42 sandwiches and 154 salads were sold for a total of $1400 .

Answer 1

Answer:

The cost of one sandwich is $15 and  the cost of one salad is $5

Step-by-step explanation:

The question is

Find out the cost of one sandwich and the cost of one salad

Let

x ----> the cost of one sandwich

y ---> the cost of one salad

we know that

$14x+14y=280$ -----> equation A

$42x+154y=1,400$ -----> equation B

Solve the system by graphing

The solution is the intersection point both graphs

using a graphing tool

the solution is the point (15,5)

see the attached figure

therefore

The cost of one sandwich is $15 and  the cost of one salad is $5

Answer 2

The cost of one sandwich is $15 and the cost of one salad is $5 and this can be determined by forming the linear equation in two variables.

Given :

• A restaurant serves sandwiches and salads.
• They sold 14 sandwiches and 14 salads for a total of $280 for lunch.
• In the evening, 42 sandwiches and 154 salads were sold for a total of $1400.

Linear equations can be formed to determine the price of a sandwich and a salad.

Let the price of one sandwich be 'x' and the price of one salad be 'y'. Then the restaurant sold 14 sandwiches and 14 salads for a total of $280 for lunch is shown by the equation:

14x + 14y = 280 --- (1)

In the evening, 42 sandwiches and 154 salads were sold for a total of $1400 and this situation is shown by the equation:

42x + 154y = 1400 --- (2)

Now, solve the equation (1) for 'x'.

$x = \dfrac{280-14y}{14}$  ----- (3)

Put the value of 'x' in equation (2).

$42\times \dfrac{280-14y}{14}+154y=14000$

840 - 42y + 154y = 1400

112y = 560

y = $5

Now, put the value of 'y' in equation (3).

$x = \dfrac{280-14\times 5}{14}$

x = $15

Therefore, the cost of one sandwich is $15 and the cost of one salad is $5.

For more information, refer to the link given below:

https://brainly.com/question/2263981